(7-5)2÷2)×(3+4+10)[tex](7 - 5)2 \div 2) \times (3 + 4 + 10)[/tex]​

Assignment: [tex]\bold{Solve \ Equation: \ \left(\left(7-5\right)\cdot \:2\div \:2\right)\left(3+4+10\right)}[/tex]<><><><><>Answer: [tex]\boxed{\bold{34}}[/tex]<><><><><>Explanation: [tex]\downarrow\downarrow\downarrow[/tex]<><><><><>[ Step One ] Follow Order Of PEMDAS, Calculate Within ParenthesisNote: [tex]\bold{PEMDAS: \ Parenthesis, \ Exponents, \ Multiply, \ Divide, \ Add, \ Subtract}[/tex][tex]\bold{\left(7-5\right)\cdot \:2\div \:2: \ 2}[/tex][ Step Two ] Rewrite Equation[tex]\bold{2\left(3+4+10\right)}[/tex][ Step Three ] Calculate Within Parenthesis[tex]\bold{3+4+10: \ 17}[/tex][ Step Four ] Rewrite Equation[tex]\bold{2 \ \cdot \:17}[/tex][ Step Five ] Solve[tex]\bold{= \ 34}[/tex]<><><><><><><>[tex]\bold{\rightarrow Mordancy \leftarrow}[/tex]