what is the equation of the line? Write in standard form. (4,5).

Answer:[tex]\large\boxed{5x+4y=20}[/tex]Step-by-step explanation:The equation of a line in slope-intercept form:[tex]y=mx+b[/tex]m - slopeb - y-intercept → (0, b)We have the x-intercept = 4 → (4, 0), and y-intercept = 5 → b = 5.Therefore we have the equation:[tex]y=mx+5[/tex]Put the coordinates of x-intercept to the equation:[tex]0=4m+5[/tex]          subtract 4m from both sides[tex]-4m=5[/tex]           divide both sides by (-4)[tex]m=-\dfrac{5}{4}[/tex]Finally we have the equation of a line if slope-intercept form:[tex]y=-\dfrac{5}{4}x+5[/tex]The standard form:[tex]Ax+By=C[/tex]Convert:[tex]y=-\dfrac{5}{4}x+5[/tex]             multiply both sides by 4[tex]4y=-5x+20[/tex]               add 5x to both sides[tex]5x+4y=20[/tex]